NCERT Solutions for Class 8 Maths Chapter 12 – Exponents and Powers. Furthermore, here we’ve provided you with the latest solution for Class 8 Maths Chapter 12 – Exponents and Powers. As a result here you’ll find solutions to all the exercises. This NCERT Class 8 solution will help you to score good marks in your exam.

Students can refer to our solution for NCERT Class 8 Maths Chapter 12 – Exponents and Powers. The Chapter 12 Solution of NCERT will help students prepare for the exams and easily crack the exam. Below we’ve provided you with the exercise-wise latest solution.

NCERT Solutions for Class 8 Maths Chapter 12 – Exponents and Powers Exercise Wise Solution

Exercise 12.1 – Page 197 of NCERT
Exercise 12.2 – Page 200 of NCERT

NCERT Solutions for Class 8 Maths Chapter 12 – Exponents and Powers Exercise 12.1 Solution

Here you’ll find NCERT Chapter 12 – Exponents and Powers Exercise 12.1 Solution.
Exercise 12.1: Solutions of Questions on Page Number: 197

Q1: Evaluate

(i) 3 2 (ii) ( – 4) 2 (iii) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713428702.gif

Answer:

(i) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713448965.gif

(ii)http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+1415271345579.gif

(iii)http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713461918.gif

Q2: Simplify and express the result in power notation with a positive exponent.

(i) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713498681.gif

(ii) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713520589.gif

(iii) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713526582.gif

(iv) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713532216.gif

(v) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+1415271353771.gif

Answer:

(i) ( – 4)5 ÷ ( – 4)8 = ( – 4)5 8 (am÷ an = am n)

= ( – 4) 3
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713543447.gif

(ii)http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713549122.gif

(iii) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713556006.gif
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713564368.gif

(iv) (3 -7 ÷ 3 10) × 3 5 = (3 7 ( 10)) × 3 5 (am ÷ an = am n)

= 33 × 3 5

= 33 + ( – 5) (am × an = am + n)

= 3-2
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713570412.gif

(v) 2-3 × ( – 7) 3 =http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713576783.gif
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713582237.gif

Q3: http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713660092.gif Find the value of.

(i) (30 + 4 1) × 22 (ii) (2 1 × 4 1) ÷ 2 2http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713606045.gif

(iii) (iv) (3 1 + 4 1 + 5 1)0http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713624621.gif

(v) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713630996.gif

Answer:

(i)
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+1415271363706.gif

(ii) (2-1 × 4-1) ÷ 2-2 = [2-1 × {(2)2}-1] ÷ 2-2

= (2-1 × 2-2) ÷ 2-2http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713642831.gif

= 2-1+ ( -2) ÷· 2-2 (am × an = am+ n)

= 2-3÷ 2 -2

= 2-3 – ( -2) (am ÷ an = am n)

= 2 -3 + 2 = 2-1 http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713654343.gif
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713648753.gif

(iv) (3 1 + 4 1 + 5 1)0http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713672035.gif

= 1 (a0 = 1)http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713681446.gif

(v)
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713687352.gif

Q4: Evaluate

(i) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713707881.gif

Answer:

(i) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+1415271373408.gifhttp://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713727328.gif
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713739344.gif

(ii)http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713745517.gif
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713756087.gif

Q5: Find the value of m for which 5m ÷ 5-3 = 55.

Answer:

5m ÷ 5-3 = 55

5m (- 3) = 55 (am ÷ an = am n) 5m+ 3 = 55

Since the powers have same bases on both sides, their respective exponents must be equal.

m + 3 = 5

m = 5 – 3

m = 2

Q6: Evaluate

(i)http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713886048.gif (ii) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713910579.gif

Answer:

(i) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713917631.gif

(ii) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713929787.gif
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713924122.gif

http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+1415271393828.gif

Q7: Simplify. (i) http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713974506.gif (ii)http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713980249.gif

Answer:

http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152713995153.gif

(i)
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152714001388.gif

(ii)http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152714008966.gif
http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152714021965.gif

NCERT Solutions for Class 8 Maths Chapter 12 – Exponents and Powers Exercise 12.2 Solution

Here you’ll find NCERT Chapter 12 – Exponents and Powers Exercise 12.2 Solution.
Exercise 12.2: Solutions of Questions on Page Number: 200

Q1: Express the following numbers in standard form.

(i) 0.0000000000085 (ii) 0.00000000000942

(iii) 6020000000000000 (iv) 0.00000000837

(v) 31860000000

Answer:

(i) 0.0000000000085 = 8.5 x 10-12

(ii) 0.00000000000942 = 9.42 x 10-12

(iii) 6020000000000000 = 6.02 x 1015

(iv) 0.00000000837 = 8.37 x 10-9

(v) 31860000000 = 3.186 x 1010

Q2: Express the following numbers in usual form.

(i) 3.02 x 10-6 (ii) 4.5 x 104

(iii) 3 x 10-8 (iv) 1.0001 x 109

(v) 5.8 x 1012 (vi) 3.61492 x 106

Answer:

(i) 3.02 x 10-6 = 0.00000302

(ii) 4.5 x 104 = 45000

(iii) 3 x 10-8 = 0.00000003

(iv) 1.0001 x 109 = 1000100000

(v) 5.8 x 1012 = 5800000000000

(vi) 3.61492 x 106 = 3614920

Q3: Express the number appearing in the following statements in standard form.

  1. 1 micron is equal to m.http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152714299448.gif
  1. Charge of an electron is 0.000, 000, 000, 000, 000, 000, 16 coulomb.
  1. Size of a bacteria is 0.0000005 m
  1. Size of a plant cell is 0.00001275 m
  1. Thickness of a thick paper is 0.07 mm Answer :http://www.schoollamp.com/images/ncert-solutions/maths+exponents+and+powers+cbse+14152714317218.gif

(i) = 1 × 10 6

(ii) 0.000, 000, 000, 000, 000, 000, 16 = 1.6 × 10 19

(iii) 0.0000005 = 5 × 10 7

(iv) 0.00001275 = 1.275 × 10 5

(v) 0.07 = 7 × 10 2

Q4: In a stack there are 5 books each of thickness 20 mm and 5 paper sheets each of thickness 0.016 mm. What is the total thickness of the stack?

Answer:

Thickness of each book = 20 mm

Hence, thickness of 5 books = (5 x 20) mm = 100 mm Thickness of each paper sheet = 0.016 mm

Hence, thickness of 5 paper sheets = (5 x 0.016) mm = 0.080 mm

Total thickness of the stack = Thickness of 5 books + Thickness of 5 paper sheets

= (100 + 0.080) mm

= 100.08 mm

= 1.0008 x 102 mm.

NCERT Class 8 Maths All Chapters Solution 

Chapter 1: Rational Numbers

Chapter 2: Linear Equations in One Variable

Chapter 3: Understanding Quadrilaterals

Chapter 4: Practical Geometry

Chapter 5: Data Handling

Chapter 6: Squares and Square root

Chapter 7: Cubes and Cube Roots

Chapter 8: Comparing Quantities

Chapter 9: Arithmetic Expressions

Chapter 10: Visualising Solid Shapes

Chapter 11: Mensuration

Chapter 12: Exponents and Powers

Chapter 13: Direct and Inverse Proportions

Chapter 14: Factorisation

Chapter 15: Introduction to Graphs

Chapter 16: Playing With Numbers